AP Physics 1  ·  Unit 4: Linear Momentum  ·  Lesson 4.2

Deep Dive: Change in Momentum and Impulse

🔬 Deep Dive
This is your textbook for this topic. Take your time. Read it more than once.
4.2.A.1Concept

What Is Impulse?

Impulse (J) is the product of the average net force applied to an object and the time interval over which that force acts:

J = F_avg * Dt

Impulse is measured in N·s (Newton-seconds), which is identical to kg·m/s — the same units as momentum. This is not a coincidence. It is the direct consequence of the impulse-momentum theorem.

Like momentum, impulse is a vector. Its direction is the same as the direction of the net force. A rightward force produces rightward impulse; a leftward force produces leftward impulse.

🔑Impulse is not the same as force, and it is not the same as momentum. It is the change in momentum caused by a force acting over time. A small force acting for a long time can produce the same impulse as a large force acting briefly. Only the product F * Dt matters.
4.2.A.2MathConcept

The Impulse-Momentum Theorem

The impulse delivered to an object exactly equals its change in momentum:

J = Dp = p_f - p_i = m*vf - m*vi

This is the most important equation in Lesson 4.2. It directly links what a force does (impulse) to how motion changes (momentum change). Use it whenever you know — or want — force, time, mass, or velocity information at two points in time.

💡Strategy: Write J = Dp. Substitute F_avg * Dt on the left and m*vf - m*vi on the right. You have four quantities — identify which three are known and solve for the fourth.

Set the force and contact time to deliver an impulse. Watch how it changes the object's momentum and final velocity directly.

Force F80 N
Contact time Dt0.5 s
Mass m2 kg
Initial speed vi+3 m/s
BEFORE
+6.0 kg·m/s
v = +3.0 m/s
AFTER
+46.0 kg·m/s
v = +23.0 m/s
J = F * Dt = 80 × 0.5 = 40.0 N·s
Dp = p_f - p_i = 46.0 - 6.0 = 40.0 kg·m/s
J = Dp  40.0 = 40.0

Same impulse, longer time = slower change. Try halving F and doubling Dt — same J, same Dp, same final velocity. This is why airbag contact time matters.

ExampleWorked Example — Impulse on a Ball

A 0.4 kg soccer ball is kicked from rest and reaches 15 m/s. The foot is in contact for 0.08 s. Find the impulse and the average force exerted.

4.2.A.4Math

Graphical Interpretations

The impulse-momentum theorem has two powerful graphical forms that the AP exam tests almost every year. Know both fluently.

F vs. t — Area = Impulse
Time (s)Force (N)Area = J = Dp
p vs. t — Slope = F_net
Time (s)p (kg·m/s)slope= F_net
F vs. t — Area = Impulse

The area under a Force vs. time graph equals the impulse delivered. For constant force: area = rectangle = F * Dt. For variable force: count grid squares, use geometry (triangles, trapezoids), or estimate.

p vs. t — Slope = Force

The slope of a momentum vs. time graph equals the net force at that instant. A steep slope means large force. A horizontal line means zero net force — momentum is constant. A curved p vs. t means changing force.

ExampleGuided Example — Impulse from a Graph

A Force vs. time graph shows a triangular pulse: force rises linearly from 0 N at t = 0 to 120 N at t = 0.3 s, then drops back to 0 N at t = 0.6 s. A 3 kg object starts at rest. Find its final speed.

Step 1Find the impulse from the graph area
The graph is a triangle. Area = ½ * base * height = ½ * 0.6 s * 120 N = 36 N·s
4.2.A.5Concept

Applications — Same Impulse, Different Forces

The most important real-world application of the impulse-momentum theorem is the trade-off between force and time. For a fixed change in momentum, increasing contact time decreases the average force — and vice versa.

Airbag in a crash
Extends contact time from ~10 ms (hard surface) to ~150 ms. Same Dp, 15x longer Dt, 15x smaller F_avg. Force below injury threshold.
Catching a baseball
Pulling your hand back increases contact time. Same impulse (ball goes from fast to rest), but spread over longer time reduces peak force on your hand.
Gymnastics landing
Bending knees on landing extends contact time. Same Dp (you stop), longer Dt, smaller F_avg on joints.
Follow-through in sports
Longer contact with the ball extends Dt, allowing more force to act longer, increasing the impulse delivered and therefore the final ball momentum.
ExampleWorked Example — Airbag vs. No Airbag

A 70 kg driver hits the steering wheel and decelerates from 15 m/s to rest. Without an airbag the stop takes 0.02 s. With an airbag it takes 0.25 s. Find the average force in each case.

← Back to Lesson 4.2Next: Lesson 4.3 →Conservation of Linear Momentum — the unit's most powerful tool.
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