AP Physics 1  ·  Unit 4: Linear Momentum  ·  Lesson 4.4

Deep Dive: Elastic and Inelastic Collisions

🔬 Deep Dive
This is your textbook for this topic. Take your time. Read it more than once.
4.4.A.1Concept

Classifying Collisions

All collisions in isolated systems conserve momentum. The question that divides them into types is: what happens to kinetic energy?

Elastic
p: conserved
KE: conserved
Objects bounce. Total KE before = total KE after. Rare in practice.
Inelastic
p: conserved
KE: decreases
KE converts to heat, sound, deformation. Most real collisions.
Perfectly Inelastic
p: conserved
KE: maximum loss
Objects stick together. One unknown velocity. Easiest to solve.
🔑The classification always comes from the data — calculate KE before and after, then compare. Never assume a collision is elastic just because objects bounce. Bouncing billiard balls are approximately elastic; most other bouncing objects are not.
4.4.A.2Math

Perfectly Inelastic Collisions

When objects stick together after a collision, they share a single final velocity. This is the easiest collision type to solve because momentum conservation gives you one equation with one unknown:

m1*v1i + m2*v2i = (m1 + m2)*vf

Solving for the final velocity:

vf = (m1*v1i + m2*v2i) / (m1 + m2)

Notice that vf is exactly the center-of-mass velocity from Lesson 4.3. This makes sense — after sticking, the system moves as one object at v_cm.

⚠️Perfectly inelastic collisions have the maximum possible KE lossfor a given set of initial conditions. Any other outcome (bouncing, partial separation) loses less kinetic energy. If a problem asks for the case of maximum energy loss, objects must stick.
ExampleGuided Example — Ballistic Pendulum

A 0.01 kg bullet moving at 400 m/s embeds itself in a 1.99 kg stationary block on a frictionless surface. Find the final velocity of the bullet-block system.

Step 1Identify collision type
Bullet embeds in block — they move together after. Perfectly inelastic.
4.4.A.3ConceptMath

Inelastic Collisions

In a general inelastic collision objects do not stick — they separate after the impact with different velocities. Momentum is still conserved, but KE is not. You have one equation (momentum conservation) and typically one unknown final velocity if the other is given.

m1*v1i + m2*v2i = m1*v1f + m2*v2f

The kinetic energy lost goes into internal energy of the system — thermal energy in the deformed materials, sound waves radiating away, and permanent deformation of the objects. This energy leaves the mechanical system but total energy of the universe is still conserved.

ExampleWorked Example — Inelastic Car Collision

Car A (1200 kg) moves right at 15 m/s and rear-ends Car B (1500 kg) moving right at 8 m/s. After the collision Car A moves right at 9 m/s. Find Car B final velocity and the kinetic energy lost.

4.4.A.4Math

Elastic Collisions

Elastic collisions conserve both momentum and kinetic energy. This gives you two equations for two unknown final velocities — a solvable system.

m1*v1i + m2*v2i = m1*v1f + m2*v2f
0.5*m1*v1i^2 + 0.5*m2*v2i^2 = 0.5*m1*v1f^2 + 0.5*m2*v2f^2

Solving this system algebraically (substituting the momentum equation into the energy equation) yields the elastic collision formulas for final velocities:

v1f = ((m1-m2)*v1i + 2*m2*v2i) / (m1+m2)
v2f = ((m2-m1)*v2i + 2*m1*v1i) / (m1+m2)
💡You do not need to memorize these formulas — you can always derive them from the two conservation equations. However, knowing them speeds up problems significantly. Note the special case: if m1 = m2, v1f = v2i and v2f = v1i — the objects swap velocities completely.

Set masses, initial velocities, and Object 1 final velocity. The simulator calculates Object 2 final velocity from momentum conservation and classifies the collision from the KE comparison.

m1 (kg)3.0
m2 (kg)2.0
v1i (m/s)+6.0
v2i (m/s)-1.0
v1f (m/s)+1.0
KE initial
55.0 J
KE final
43.8 J
p_i
+16.0 kg·m/s
v2f
+6.50 m/s
DKE
-11.3 J
InelasticKE decreased by 20.5% — converted to heat, sound, or deformation.

Drag v1f toward the elastic value to watch DKE approach zero. When p is conserved AND KE is conserved, v1f has exactly one correct value.

ExampleGuided Example — Elastic Collision

A 3 kg ball moving right at 8 m/s collides elastically with a 1 kg ball at rest. Find the final velocities of both balls.

Step 1Write both conservation equations
Momentum: 3(8) + 1(0) = 3*v1f + 1*v2f → 24 = 3*v1f + v2f
KE: 0.5(3)(64) = 0.5(3)*v1f^2 + 0.5(1)*v2f^2 → 96 = 1.5*v1f^2 + 0.5*v2f^2
4.4.A.5Math

Calculating Kinetic Energy Lost

In any inelastic collision, the kinetic energy lost to internal energy can be calculated directly:

DKE = KE_f - KE_i = (0.5*m1*v1f^2 + 0.5*m2*v2f^2) - (0.5*m1*v1i^2 + 0.5*m2*v2i^2)

DKE is always negative for inelastic collisions — energy leaves the mechanical system. Zero for elastic — nothing is lost. Never positive in a simple collision — you cannot create kinetic energy from nothing.

🔑On the AP exam, "how much energy was lost?" is a standard follow-up after solving for final velocities. Always calculate KE before and KE after separately, then subtract. Do not try to calculate energy loss without first finding the final velocities.
ExampleWorked Example — Maximum Energy Loss

A 4 kg object moving at 10 m/s collides with a 6 kg stationary object. Calculate the kinetic energy for both perfectly inelastic and elastic outcomes, and find the energy lost in each case.

Back to Lesson 4.4Progress Check 4 on AP Classroom →

Unit 4 complete. Progress Check 4 covers all four lessons — momentum, impulse, conservation, and collisions. Collision FRQs require a written justification of collision type, not just a numerical answer.

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