AP Physics 1  ·  Unit 3: Work, Energy & Power  ·  Lesson 3.5

Deep Dive: Power

🔬 Deep Dive
This is your textbook for this topic. Take your time. Read it more than once.
3.5.A.1Concept

What Is Power?

Power is the rate at which energy is transferred or converted. It answers the question: how fast is energy moving?

P = ΔE / Δt

The unit of power is the Watt (W) — one Joule per second. Power is a scalar. Like energy, it has no direction.

The key insight is that power depends on both the amount of energy transferred and the time over which it's transferred. Two engines can do the same total work — but the one that does it faster is more powerful. Power is entirely about rate.

🔑Don't confuse power and energy. A 1,000 W microwave and a 100 W light bulb both use electrical energy — but the microwave transfers it ten times faster. Run both for an hour and the microwave has transferred ten times as much energy total. Power is the rate; energy is the total.
3.5.A.2Math

Average Power

Average power is the total work done (or energy transferred) divided by the total time elapsed:

P_avg = W / Δt = ΔE / Δt

This is the form to use when you know the total work and the time interval over which it was done. It doesn't matter how the power varied during that time — you're averaging over the whole interval.

Same work, two different time intervals. Watch how power changes even though the total energy transferred is identical.

Work done (W)600 J
Time A (fast)4 s
Time B (slow)12 s
Scenario A (fast)
150.0 W
600J / 4s
Scenario B (slow)
50.0 W
600J / 12s
Same work: 600 J both cases
Power ratio: 3.0× more power in Scenario A

Energy transferred is identical — power is entirely about the rate. Double the time → half the power, same work done.

ExampleWorked Example — Average Power of a Motor

A motor lifts a 40 kg crate from the ground to a height of 6 m in 8 seconds. What is the average power output of the motor? (g = 10 m/s²)

3.5.A.3MathConcept

Instantaneous Power

Instantaneous power is the power delivered at a specific instant — when force and velocity are known at that moment:

P_inst = Fv cosθ

This formula comes directly from combining P = W/Δt with W = Fd cosθ:

P = W/Δt
W = Fd cosθ
P = Fd cosθ / Δt
d/Δt = v
∴ P = Fv cosθ
💡When force is parallel to velocity (θ = 0°), cosθ = 1 and P = Fv. This is the most common form. The full P = Fv cosθ is used when force and velocity point in different directions.

Set the force, speed, and angle between them. The graph shows constant power over time — the shaded area is the energy transferred in 5 seconds.

Force (F)80N
Speed (v)6m/s
Angle (θ)0°
Time (s)Power (W)480 WE=2400J0510
F‖ = F cosθ
80.0 N
parallel component
P = F‖ · v
480.0 W
instantaneous power
E in 5 s
2400.0 J
area = P × Δt

Drag angle to 90° — power drops to zero even though force and speed are both nonzero. Only the component of force along the direction of motion delivers power.

ExampleGuided Example — Engine Power at Speed

A car engine exerts a 3,000 N drive force while the car moves at 25 m/s on a flat road. What is the instantaneous power output of the engine?

Step 1Identify the quantities
F = 3,000 N (drive force, parallel to motion). v = 25 m/s. θ = 0° (force and velocity in same direction).
3.5.A.4Math

Power vs. Time Graphs

On a Power vs. Time graph, the area under the curve equals the total energy transferred during that interval. This is directly analogous to the area under a velocity-time graph giving displacement, or a force-displacement graph giving work.

Constant power
RectangleE = P × Δt
Horizontal line on P vs. t graph. Area = base × height.
Varying power
Area under curveE = area under P(t)
Any shape. Must calculate area geometrically or from data.
🔑AP exam questions frequently show a P vs. t graph and ask for total energy. If the graph is a rectangle, E = P × t. If it's a triangle (power increasing linearly from zero), E = ½ × P_max × t. Always check the graph shape before calculating.
ExampleWorked Example — Energy from a P vs. t Graph

A machine's power output increases linearly from 0 W at t = 0 to 600 W at t = 10 s. How much total energy does it transfer in those 10 seconds?

3.5.A.5Math

Applications — Power + Energy Together

The most common AP exam power problem combines power with the work-energy theorem from Lesson 3.4: given a power output and a resistive force, find the maximum constant speed, or given a speed, find how long it takes to do a given amount of work.

💡Maximum speed at constant power: At maximum speed, acceleration = 0, so net force = 0, so drive force = resistance force. Set P = F_drive × v_max and solve for v_max = P / F_resistance. This is the classic "terminal speed under constant power" problem.
ExampleGuided Example — Maximum Speed

A car's engine delivers a constant 60 kW of power. Air resistance and friction provide a combined resistive force of 1,200 N. What is the car's maximum speed on a flat road?

Step 1Identify the condition for maximum speed
At maximum speed the car no longer accelerates. Net force = 0, so drive force = resistive force = 1,200 N.
← Back to Lesson 3.5🏁 Progress Check 3 on AP Classroom →

Unit 3 complete. Progress Check 3 covers all five lessons — kinetic energy, work, potential energy, conservation, and power. Take it before moving to Unit 4.

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