The total energy of a system exhibiting SHM is the sum of its kinetic and potential energies:
Conservation of energy indicates that this total is constant throughout the motion. As the system oscillates, energy continuously shifts between kinetic and potential form — but the sum of the two never changes.
Slide through the motion of a spring–object system (A = 2 m, k = 5 N/m) and watch U and K trade places while their sum stays flat — the same energy-vs-position graph shown in this unit's header art.
A 0.5 kg mass on a spring (k = 20 N/m) oscillates with amplitude A = 0.3 m. Find its speed when x = 0.15 m.
Because the total is fixed, kinetic and potential energy trade off in a completely predictable way. Kinetic energy is at a maximum exactly when potential energy is at a minimum — and potential energy is at a maximum exactly when kinetic energy is at a minimum, which for SHM is always zero:
Same system, viewed as a split of the total energy. At equilibrium the bar is all kinetic; at the extremes it's entirely potential — and kinetic energy never goes below zero, exactly as 7.4.A.4.i requires.
This trade-off is the same idea you've now seen play out across every energy-based topic in this course — just replayed here with a spring or pendulum instead of a hill or an orbit.
Changing a system's amplitude changes the maximum potential energy it reaches — and since Etotal equals that maximum PE (all energy is potential at the turning points), changing amplitude changes the total energy too. For a spring–object system:
For a spring–object system with k = 20 N/m, slide the amplitude and watch how fast total energy grows — it's proportional to A², not A.
For the same spring system (k = 20 N/m), compare the total energy at A = 0.3 m to the total energy at A = 0.6 m.