AP Physics C: Mechanics · Unit 5: Torque and Rotational Dynamics · Lesson 5.2

Deep Dive: Connecting Linear and Rotational Motion

🔬 Deep Dive
This is your textbook for this topic. Take your time. Read it more than once.
5.2.A.1Math

Arc Length

For a point sitting a distance r from a fixed axis of rotation, the linear distance it actually travels — its arc length — as the system rotates through an angle Δθ is:

Δs = rΔθ
ΔθΔsrΔs = rΔθ — bigger r, more arc length for the same angle.
💡This is really just the definition of a radian in disguise: an angle of exactly 1 radian sweeps out an arc length exactly equal to the radius. Everything else in this lesson builds directly on this one relationship.
5.2.A.2Math

Linear Velocity and Tangential Acceleration

Differentiate the arc-length relationship with respect to time, and two of the most useful equations in the whole unit fall right out:

v = rω
a(T) = rα
🔑a(T) here specifically means tangential acceleration — the component of acceleration along the direction of motion, changing a point's speed. (Recall from Lesson 2.10 that a point moving in a circle can also have a separate centripetal component, which doesn't come from this relationship at all.)

Explore the pulley application directly below, matching this unit's own header art.

The pulley system from this unit's header art. A string wrapped around the pulley's rim connects to a hanging mass — the mass's linear acceleration is exactly the pulley rim's tangential acceleration.

pulley radius r0.080 m
α (rad/s²)4.0
ma = aT
a(T) = rα = (0.080)(4.0) = 0.320 m/s²

This is exactly how a pulley's rotation gets linked to a hanging mass's linear acceleration — a relationship you'll use constantly starting in Lesson 5.6.

ExampleGuided Example — Rolling Wheel Speed

A bicycle wheel of radius 0.35 m rotates at 4 rad/s. Find the linear speed of a point on the wheel's rim.

Step 1Identify the relevant equation
v = rω relates a point's linear speed to its distance from the axis and the system's angular velocity.
5.2.A.3Concept

Same ω Everywhere, Different v Depending on r

For a rigid system, every single point shares exactly the same angular velocity and angular acceleration — that's what "rigid" means. But since v = rω and aT = rα both scale directly with r, points farther from the axis move faster and accelerate more, even though they're all spinning at the same rate.

⚠️This is a common point of confusion: don't assume every point on a rotating object has the same speed. They share ω and α — never v or aT, unless they happen to sit at exactly the same radius.

Explore this directly below, matching this unit's header art of masses at different radii on the same rotating disk.

A rigid disk rotating at ω, matching this unit's header art — masses at different radii, all sharing the exact same angular velocity. Watch how differently their linear speeds compare.

ω (rad/s)1.5
r₁ (cm)30
r₂ (cm)70
v₁ = r₁ω = (30)(1.5) = 0.45 m/sv₂ = r₂ω = (70)(1.5) = 1.05 m/s

Both points complete a revolution in exactly the same time — same ω — but the outer point has to cover far more distance to do it, so it must move faster.

← Back to Lesson 5.2Ready for 5.3? Torque introduces the rotational equivalent of force — and the cross product that defines it.