Physics · Unit 6: Optics ·  Activity 6-1-1

Deep Dive: Reflection & Mirrors

🔬 Deep Dive
This is your textbook for this topic. Read it alongside the activity.
AConcept

Light Rays and Reflection

In a uniform material, light travels in straight lines. We draw a path of light as a ray, a line with an arrow. Optics is mostly the study of what happens to rays when they reach a surface, and the simplest thing a surface can do is send them back. That is reflection.

Not every surface reflects the same way. A very smooth surface, like a mirror, sends parallel rays all off in the same direction. That is specular reflection, and it is what makes a clear image. A rough surface, like paper or a wall, sends the rays off in every direction. That is diffuse reflection, and it is why you can see a wall from anywhere in the room but can’t see your face in it. Both kinds follow the same rule at the tiny scale of each bump. The bumps just point every which way.

BMath

The Law of Reflection

To describe a bounce, you need a reference line. The normal is a line drawn at 90° to the surface, at the point where the ray strikes. The angle between the incoming ray and the normal is the angle of incidence. The angle between the outgoing ray and the normal is the angle of reflection. The law says:

θ_reflection = θ_incidence

The incident ray, the reflected ray, and the normal all lie in the same plane. And always measure from the normal, never from the surface.

Example 1: the angle between the rays
Given
  • A ray strikes a mirror at an angle of incidence of 35°
Solve
θ_reflection = θ_incidence = 35°
Angle between the incident and reflected rays = 35° + 35° = 70°
✓ The ray reflects at 35° on the other side of the normal, so the two rays are 70° apart.
Example 2: an angle measured from the surface
Given
  • A ray makes a 25° angle with the surface of the mirror
Solve
The normal is 90° from the surface
θ_incidence = 90° − 25° = 65°
θ_reflection = 65°, so the reflected ray also makes 25° with the surface
✓ The angle of incidence is 65°. A ray skimming the surface has a large angle of incidence.
Example 3: a rotating mirror
Given
  • The incoming ray stays fixed, and the mirror is rotated by 10°
Solve
The normal rotates by 10° too
The angle of incidence changes by 10°, say from 25° to 15°
The angle of reflection changes by 10° as well, in the same sense
The reflected ray’s direction changes by 10° + 10° = 20°
✓ Rotating a mirror by an angle turns the reflected ray by twice that angle.
💡The doubling is useful. A tiny tilt of a mirror makes a big movement of the reflected beam, which is why lasers, galvanometers, and a lot of precision instruments use a small mirror as a pointer.
CExample

Rotating Mirror Explorer

Tilt the mirror and compare how far the mirror turned with how far the beam turned. Then change the incoming angle and check that the angles on both sides of the normal are always equal.

A fixed beam strikes a mirror. Tilt the mirror and watch the reflected beam. The dashed gray beam shows where it went when the mirror was upright.

normalincoming rayreflected ray
θ_incidence = θ_reflection = 25.0°
Angle between incident and reflected rays = 2 × 25.0° = 50.0°
The mirror tilted 0°, and the reflected ray turned 0°. That is zero because nothing moved.
DConcept

Images in a Plane Mirror

When light from an object reflects off a mirror and reaches your eye, your brain assumes the light came straight from its source. It traces the reflected rays backward in straight lines. They appear to meet at a point behind the mirror. That point is the image. In a flat mirror, the image has three features:

d_i = d_o h_i = h_o
💡A mirror doesn’t flip left and right any more than it flips up and down. What it reverses is the direction toward and away from the mirror, front to back. Your reflection’s right hand is still on the right of the picture. It only looks “swapped” because you imagine turning around to face yourself.

How tall does a mirror need to be?

Surprisingly, only half your height. To see your head, the ray from the top of your head must reflect into your eye. By the law of reflection, it hits the mirror exactly halfway between your eye level and the top of your head. To see your feet, the ray reflects halfway between your eyes and your feet. The mirror only has to span those two points.

eyeheadfeetmirrorhalf the heightimage of headimage of feet
A wall mirror
Given
  • A person is 1.70 m tall, with eyes at 1.60 m above the floor
Solve
Top edge: halfway between the eyes and the top of the head = (1.60 + 1.70) ÷ 2 = 1.65 m
Bottom edge: halfway between the eyes and the feet = (1.60 + 0) ÷ 2 = 0.80 m
Mirror height = 1.65 − 0.80 = 0.85 m
✓ The mirror needs to be 0.85 m tall, half the person’s height, and its bottom edge must be 0.80 m off the floor. It doesn’t matter how far away they stand.
EConcept

Two Mirrors: Periscopes and Corners

A mirror at 45° to a horizontal ray has a normal at 45° to the ray, so the angle of incidence is 45° and the ray turns by 90°. A periscope uses two parallel mirrors at 45°. The first turns the ray up by 90° and the second turns it back to horizontal. The ray leaves in the same direction it entered, but shifted over. That is how you see over a wall or around a corner.

More generally, two mirrors with an angle α between them turn a ray by a total of

deviation = 2α

Parallel mirrors (α = 0) turn the ray by nothing, which is the periscope. Mirrors at right angles (α = 90°) turn the ray by 180°, sending it straight back toward where it came from. That’s how a bicycle reflector and the reflectors left on the Moon work.

🔑In Project 6-1-4, a periscope is one of the devices you can build. Its two mirrors have to be parallel and each at 45° to the light path, or the image will tilt or the beam will miss your eye.
FConcept

Curved Mirrors

Take a flat mirror and curve it, and the normal now points in a different direction at every point. Rays still obey the law of reflection at each point, but they no longer stay parallel. A concave mirror curves inward, like the inside of a bowl. A convex mirror bulges outward, like the back of a spoon.

A few terms describe a curved mirror. The center of curvature C is the center of the sphere the mirror is part of, and R is its radius. The principal axis runs through the middle of the mirror and C. A concave mirror brings rays that arrive parallel to the axis together at the focal point F, halfway between the mirror and C. So the focal length is

f = R ÷ 2

A convex mirror spreads parallel rays apart, and they look as if they came from a focal point behind the mirror. We make that distinction with a sign: f is positive for a concave mirror and negative for a convex mirror.

To find an image, draw rays from the tip of the object. Two are easy: a ray parallel to the axis reflects through F (or appears to come from F behind a convex mirror), and a ray through F reflects parallel to the axis. Where the reflected rays meet is the image tip.

For a concave mirror, the image depends on where the object is:

Object positionImageExample
d_o > 2f (beyond C)Real, inverted, smallerYou, far from a spoon’s bowl
d_o = 2f (at C)Real, inverted, the same size
f < d_o < 2f (between F and C)Real, inverted, largerA projector-style image
d_o = f (at F)No image: the rays emerge parallelA flashlight or headlight reflector
d_o < f (inside F)Virtual, upright, largerA makeup or shaving mirror
🔑This is the answer to the unit’s third question. Stand far from a concave mirror and you’re beyond C, so you appear smaller and upside-down. Step inside the focal point and the image jumps behind the mirror: upright and magnified. A convex mirror doesn’t do any of that. At every distance it gives a smaller, upright image, but it takes in a wide view.
GMath

The Mirror Equation

Drawing rays gives you the idea. An equation gives you numbers. For a curved mirror, with object distance d_o and image distance d_i measured from the mirror:

1/f = 1/d_o + 1/d_i
m = h_i ÷ h_o = −d_i ÷ d_o

The signs carry the meaning. f is positive for concave and negative for convex. d_i is positive for a real image, in front of the mirror, and negative for a virtual image behind it. The magnification m is negative for an inverted image and positive for an upright one. If |m| is greater than 1, the image is larger. You’ll meet this same equation again in 6-1-3 for lenses.

Example 1: a concave mirror, object far away
Given
  • f = +10 cm (concave), d_o = 30 cm, h_o = 4.0 cm
Solve
1/d_i = 1/f − 1/d_o = 1/10 − 1/30 = 2/30
d_i = +15 cm
m = −d_i ÷ d_o = −15 ÷ 30 = −0.50
h_i = m × h_o = −2.0 cm
✓ A real image 15 cm in front of the mirror, inverted and half the size.
Example 2: a concave mirror, object inside the focal point
Given
  • f = +10 cm (concave), d_o = 5.0 cm, h_o = 4.0 cm
Solve
1/d_i = 1/10 − 1/5 = −1/10
d_i = −10 cm
m = −(−10) ÷ 5.0 = +2.0
h_i = +8.0 cm
✓ A virtual image 10 cm behind the mirror, upright and twice the size. That’s a makeup mirror.
Example 3: a convex mirror
Given
  • f = −10 cm (convex), d_o = 30 cm, h_o = 4.0 cm
Solve
1/d_i = 1/f − 1/d_o = −1/10 − 1/30 = −4/30
d_i = −7.5 cm
m = −(−7.5) ÷ 30 = +0.25
h_i = +1.0 cm
✓ A virtual image 7.5 cm behind the mirror, upright and a quarter of the size.
HExample

Curved Mirror Explorer

Start with a concave mirror and f = 10 cm. Move the object from far away toward the mirror, and watch the image grow, then blow up near the focal point, then jump behind the mirror. Then switch to a convex mirror and see that nothing like that ever happens.

Pick a mirror, set its focal length, and slide the object toward and away from it. Watch the image flip, grow, shrink, and jump behind the mirror. Two of the three principal rays are drawn from the tip of the object.

FCobjectimage
Mirror:
f = +10 cm  ·  1/f = 1/d_o + 1/d_i
1/d_i = 1/(10) − 1/30, so d_i = 15.0 cm  ·  m = −d_i/d_o = -0.50
The image is real, inverted, and smaller.
IWatch Out

Three Common Mix-Ups

⚠️“Measure the angle from the mirror.” The law of reflection uses the normal, the line at 90° to the mirror. A ray at 25° to the surface has an angle of incidence of 65°, and mixing the two up is the most common mistake in reflection problems.
⚠️“The image is a real thing behind the mirror.” It isn’t. There is no light behind a plane mirror. The image is where your brain traces the reflected rays back to, which is why it’s called virtual and can’t be caught on a screen.
⚠️“A bigger mirror makes a bigger image.” The size of a plane-mirror image is always the same as the object, no matter how big the mirror is. A bigger mirror just lets you see more of the image. Only a curved mirror changes the size.
JConcept

Quick Check

Four questions. They are not graded. Answer them to find out what still needs work.

Q1A ray strikes a plane mirror 30° from the normal. What is the angle between the incident ray and the reflected ray?
Q2You stand 2.0 m in front of a plane mirror. How far are you from your image?
Q3A concave mirror has a focal length of 10 cm, and an object is 30 cm from it. What kind of image forms?
Q4Why are convex mirrors used as store security mirrors and for passenger-side car mirrors?
Score: 0 of 4
KConcept

Looking Ahead

You now know how light bounces. Next you’ll see what it does when it passes through something instead.

← Back to Activity 6-1-1Go to the Activity →