Physics · Unit 5: Momentum ·  Activity 5-2-2

Mystery Mass and the Skid Mark

🎚️ Activity
2 class days  ·  Work in small groups

Day 1 stretches conservation of momentum to harder problems: both objects moving, an unknown quantity, a system that splits. Day 2 uses it to identify a hidden mass, and then works backward from a skid mark to the speed before a crash.

🎯 Goals

🧰 Materials

🚗Two carts or toy cars with free-rolling wheels. One is the “mystery” cart, prepared by your teacher
🎁A sealed or covered mystery cart with a hidden load, and Velcro or putty to make the carts stick
🛤️A level track or flat board, with a small ramp to release cart A at a steady speed
📏Meter stick and masking tape
📱A phone with slow-motion video (120 or 240 fps)
⚖️A scale that reads in grams, for the reveal at the end
🧮Calculator
📓Physics notebook
DAY 1Harder before-and-after problems
Section 1 of 4

Both Objects Moving

1
Read the method.
Pick a positive direction. Write the momentum of each object before and after, with signs. Set the total before equal to the total after. If the collision is elastic, add the equation that the relative velocity reverses.
Total momentum: m_A v_A + m_B v_B = m_A v_A′ + m_B v_B′
Stick together: m_A v_A + m_B v_B = (m_A + m_B) v_f
Elastic: also v_A − v_B = −(v_A′ − v_B′)
Skid to a stop: v = √(2μgd), from F_f × d = ½mv² with F_f = μmg
2
Solve five problems where both carts move.
The last two need two equations: conservation of momentum and the reversal of relative velocity. Enter each answer with its sign.
Both Moving
Right is positive.
Cart A: 2.0 kg at +3.0 m/s. Cart B: 1.0 kg at −2.0 m/s. What is the total momentum of the system before they collide?
They collide head-on and stick together. What is their final velocity?v_f = p_total ÷ (m_A + m_B)
Now cart B is moving at +1.0 m/s in the same direction, so A catches up, and they stick. What is their final velocity?
A 3.0 kg cart at +2.0 m/s and a 1.0 kg cart at −2.0 m/s collide head-on in an elastic collision. What is the 3.0 kg cart’s velocity afterward?Momentum: 3v_A′ + v_B′ = 4.0, and v_A′ − v_B′ = −(2.0 − (−2.0))
What is the 1.0 kg cart’s velocity afterward?
Section 2 of 4

Solving for the Unknown

3
Solve for a missing mass or velocity.
The same equation works backward. Put the numbers you know into the conservation equation and solve for the one you don’t. The last problem starts with a moving system that splits, so the momentum before is not zero.
Find the Unknown
Right is positive.
A 1.5 kg cart at +4.0 m/s hits a stationary cart, and they stick and move off at +1.5 m/s. What is the second cart’s mass?m_B = m_A(v_A − v_f) ÷ v_f
A 4.0 kg cart at +3.0 m/s hits a 2.0 kg cart at rest. Afterward the 4.0 kg cart moves at +1.0 m/s. What is the 2.0 kg cart’s velocity?
A 50 kg skater at rest catches a 5.0 kg ball moving at +8.0 m/s. What is their velocity afterward?
A 2.0 kg cart rolling at +1.0 m/s releases a spring and splits into two 1.0 kg halves. One half moves at +3.0 m/s. What is the other half’s velocity?The system started moving, so p_before = 2.0
✅ End of Day 1 check: Both Moving and Find the Unknown are all green, and you can explain in a sentence how you picked your positive direction.
DAY 2A mystery mass and a skid mark
Section 3 of 4

Mystery Mass Lab

4
Get your mystery cart and mass cart A.
Your teacher gives you a sealed cart with a hidden load. Do not open it and do not put it on the scale. Mass your known cart, A, and write it down.
5
Collide A into the mystery cart and measure the speeds.
Set up the track with a 0.50 m before zone and a 0.50 m after zone, as in Activity 5-1-3. Put the mystery cart, B, at rest on the collision line with Velcro or putty so the carts stick. Release A from the same ramp height each time. Film from the side and step through frame by frame. Find A’s speed before and the stuck-together speed after. Do three runs.
6
Work out the hidden mass from each run.
Momentum is conserved, so m_A v_A = (m_A + m_B) v. Solving for the unknown gives m_B = m_A (v_A − v) ÷ v. Calculate m_B for each run and average.
7
Reveal the answer.
Only after you’ve written your estimate, put the mystery cart on the scale and find its actual mass. Calculate the percent error.
Sample data (use only if you can’t run the lab)
Cart A 0.250 kg. Run 1: v_A = 0.80, v = 0.35. Run 2: 0.78, 0.34. Run 3: 0.81, 0.36 (all in m/s). After the reveal, the mystery cart’s mass is 0.300 kg.
Runm_A (kg)v_A before (m/s)v after, stuck (m/s)m_B = m_A(v_A − v) ÷ v (kg)
Average m_B estimate (kg)Actual m_B from the scale (kg)% error
Mystery Mass Checker

Work an average by hand first. Then enter it here. After the reveal, add the real mass of the mystery cart.

What good data looks like
Most groups land within about 5–15% of the true mass. A small final speed makes the estimate more sensitive to timing error, since the same one-frame mistake is a bigger fraction of a slow speed.
📓 Physics Notebook
How close was your estimate? Which measurement had the biggest effect on the answer, and why? How could you have made the estimate more reliable?
Section 4 of 4

Collide, Then Skid

8
Reconstruct a crash from its skid mark.
Two cars lock together and skid to a stop. You can’t measure their speed before the crash, but you can measure the skid. Work in two stages. After the collision, friction takes all of the kinetic energy, so v = √(2μgd). Across the collision, momentum is conserved, so you can work back to the speed before.
Crash Reconstruction
Use g = 9.8 N/kg. Dry asphalt has μ = 0.70 and wet asphalt has μ = 0.40.
A 1,200 kg car hits a stationary 1,000 kg car. They lock together and skid 12 m to a stop on dry asphalt (μ = 0.70). How fast were they moving just after the collision?v = √(2μgd), g = 9.8 N/kg
What was their combined momentum just after the collision?
How fast was the 1,200 kg car going just before the collision?Momentum is conserved across the collision
Suppose the road was wet (μ = 0.40) and the skid was the same 12 m. How fast was the 1,200 kg car going before the collision?
📓 Physics Notebook
Why can you use conservation of momentum across the collision but not across the skid? What force acts during the skid that is not part of the collision? Why do real investigators report a range of speeds instead of a single number?
Question 1
Show your calculation for the mystery mass and compare it with the actual mass. Which measurement had the biggest effect on your uncertainty, and why?
Question 2
Explain why momentum can be used across the collision but not across the skid. What changes about the forces on the cars?
Question 3
On a wet road, the same 12 m skid means a slower pre-crash speed. Explain why the friction assumption matters, and why investigators give a range.
Question 4
A cart rolling at +1.0 m/s splits into two 1.0 kg halves, and one half moves at +3.0 m/s. Where does the other half go, and where did the extra kinetic energy come from?
📤 Turn In
← Back to Activity 5-2-2 OverviewReview the Deep Dive →Next up: Project 5-2-3, Collision Lab.